3x^2+0.80x=0

Solution for 3x^2+0.80x=0 equation:

3x^2+0.80x=0

a = 3; b = 0.80; c = 0;
Δ = b2-4ac
Δ = 0.802-4·3·0
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.80)-\sqrt{0.64}}{2*3}=\frac{-0.8-\sqrt{0.64}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.80)+\sqrt{0.64}}{2*3}=\frac{-0.8+\sqrt{0.64}}{6}
$